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2w^2+12w-864=0
a = 2; b = 12; c = -864;
Δ = b2-4ac
Δ = 122-4·2·(-864)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-84}{2*2}=\frac{-96}{4} =-24 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+84}{2*2}=\frac{72}{4} =18 $
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